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If (5x²+65x+60) / （x²+10x-24） = （5x+5）/ （x-2） , then which of the following are possible values of x? Indicate all such values.
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当前版本由 笑笑笑笑笑 更新于2024-08-23 10:14:35 感谢由 笑笑笑笑笑 对此题目的解答所做出的贡献。
5x²+65x+60=5(x²+13x+12)=5(x+1)(x+12)
x²+10x-24=(x-2)(x+12)
(5x²+65x+60) / （x²+10x-24）=(5x+5)(x+12)/(x-2)(x+12) = （5x+5）/ （x-2）
分母x²+10x-24=(x-2)(x+12)不能等于0，因此x不能等于2和-12
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我有更好的解析
当前版本由 Helen 更新于2019-03-28 15:31:34 感谢由 Helen 对此题目的解答所做出的贡献。
x^2+10x-24≠0
即(x-2)(x+12)≠0
x≠2,x≠-12
题目讨论
(如果对题目有任何的疑惑，欢迎在这里提出来，大家会帮你解答的哦~)
233322vs
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279028qpjft
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346983bmb
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不，看答案才明白就只考察分母不为零
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确实不全，即使跟原题答案一样，也没有它这么出题的。原题在这里https://gre.myprepclub.com/forum/if-5x-2-65x-60-x-2-10x-24-5x-5-x-2-the-8070.html
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jessica9
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如果是0 那就不能约掉啊
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一朵乌云
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