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The “reflection” of a positive integer is obtained by reversing its digits. For example, 321 is the reflection of 123. The difference between a five-digit integer and its reflection must be divisible by which of the following?
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当前版本由 布鲁布鲁 更新于2021-10-21 17:32:05 感谢由 布鲁布鲁 对此题目的解答所做出的贡献。
五位数54321 倒过来12345 个位数是1和5 只有9的倍数个位数有1和5
当前版本由 昵称吧 更新于2018-05-09 09:54:40 感谢由 昵称吧 对此题目的解答所做出的贡献。
E
假设五位数是 abcde
(10000a+1000b+100c+10d+e)-(10000e+1000d+100c+10b+a)
=9999a+990b-990d-9999e
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=9(1111a+110b-110d+1111e)
一定是 9 的倍数
题目讨论
(如果对题目有任何的疑惑，欢迎在这里提出来，大家会帮你解答的哦~)
254518ryg
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820285ltka
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mighdwag
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312755tlbw
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如果头尾分别为奇偶，那么倒转前后的差值的个位数就是奇数，所以不一定是2的倍数
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333738goqa
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我也是这么想的
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他没有说数字一定是按照顺序排列的呀 可以是38976和67983 也可以是任意一个五位数，所以这题要按照用代数来算 设一个五位数是abcde 那a代表的是10000*a b 为1000*b 以此类推， 然后再反过来列出相反的那个reflaction 两个东西相减就很明显是9了
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因为题目问的是must be，不是could be，不然就是多选题了
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